
CALENDAR SOLVED • • • • •
However, we have to be able to precede any of the digits with 0 (for dates 01 through 09), or with 1 (for dates 10 through 19), or with 2 (for dates 20 through 29). Therefore whichever cube a digit is on, the other cube must contain the digits 0, 1, and 2. That means that 0, 1, and 2 must appear on both cubes. (To display 30 and 31, the 3 that appears on only one cube can be paired with the 0 or the 1 from the other cube.) So each cube has 0 1 2. Three faces remain unassigned on each cube, for a total of six faces. Onto those six faces we have to fit the remaining seven digits, 3 4 5 6 7 8 9. How can we fit seven digits onto six faces? Put 3 4 5 on one cube and 6 7 8 on the other. When a 9 is required, just turn the 6 upside down.


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